When using enums in a switch, it is almost natural to assume they will be used like a regular switch. Unfortunately to accomodate enums, Java had to enhance its specification and enums in switch behave differently than regular switch statements in two significant and non-trivial ways.

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Should we use to represent a constant String such as browser's user agent or simply use public static final String as before?
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You may run Java processes in the foreground or in many cases they may be run using cron jobs or during system startup, as background processes. How can you find out stacktraces of any running Java process? But first how can you even know their name & process id's?
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Vodafone Group Plc (www.vodafone.it) is arguably the world's leading mobile telecommunications company, with a significant presence in Europe, the Middle East, India, Africa, Asia Pacific and the United States through the Company's subsidiary undertakings, joint ventures, associated undertakings and investments. Vodafone has chosen FioranoMQ, Java Messaging server, for a mission-critical system delivering over 2500 messages / sec.

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While debugging code Java programmers often use System.out.println(). It is important to write separate message in each System.out.println() so you can understand from the output where the problem lies.

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Why does finally have to have braces?

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Let's begin with an example. Assume a class MQ is in the package  com.taragana.mq. The utlitiy class Util also belongs to the same package. I can import Util from MQ like this:

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I am using Ant (Java based build system) for our project. Ant is an exceptionally powerful build system and should be the only build system you will ever need. You don't really need code monsters like Maven (or pile of …. as Bileblogger loves to say). With little effort here's what I achieved in few hours (aside from the obvious capability of compiling, running, building jar files etc.):
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First tell me what is the best way to concatenate large number of String objects? Is it a + b?

Most Java developers know not to use a + b (+ operator) because of huge performance problems, they use StringBuffer instead. In fact I did some tests in the past which confirms this folklore. However some of you may not know there is new kid on the block - StringBuilder. Read more (116 words) »

This isn't a trick question. For a long time you couldn't delete a property from java.util.Properties class. In the recent versions too Java doesn't reveal that it has added the functionality. However as java.util.Properties now extends Hashtable, you can delete a property by:

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